2x^2+2y^2+20y=0

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Solution for 2x^2+2y^2+20y=0 equation:


Simplifying
2x2 + 2y2 + 20y = 0

Reorder the terms:
2x2 + 20y + 2y2 = 0

Solving
2x2 + 20y + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-20y' to each side of the equation.
2x2 + 20y + -20y + 2y2 = 0 + -20y

Combine like terms: 20y + -20y = 0
2x2 + 0 + 2y2 = 0 + -20y
2x2 + 2y2 = 0 + -20y
Remove the zero:
2x2 + 2y2 = -20y

Add '-2y2' to each side of the equation.
2x2 + 2y2 + -2y2 = -20y + -2y2

Combine like terms: 2y2 + -2y2 = 0
2x2 + 0 = -20y + -2y2
2x2 = -20y + -2y2

Divide each side by '2'.
x2 = -10y + -1y2

Simplifying
x2 = -10y + -1y2

Reorder the terms:
x2 + 10y + y2 = -10y + 10y + -1y2 + y2

Combine like terms: -10y + 10y = 0
x2 + 10y + y2 = 0 + -1y2 + y2
x2 + 10y + y2 = -1y2 + y2

Combine like terms: -1y2 + y2 = 0
x2 + 10y + y2 = 0

The solution to this equation could not be determined.

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